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数学
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(lg2)^2+lg25+2/3lg8+lg5*lg20=?
人气:172 ℃ 时间:2019-12-06 10:19:31
解答
(lg2)^2+lg25+2/3lg8+lg5*lg20
=(lg2)^2+2lg5+2lg2+lg5*(lg5+2lg2)
=(lg2+lg5)^2+2(lg2+lg5)
=(lg10)^2+2lg10
=1+2
=32/3lg8这个怎么化?
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