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已知-3≤log1/2x≤-1/2,求函数f(x)=(log2 x/2)(log2 x/4)的最大值和最小值,并求出对应的x值
人气:120 ℃ 时间:2019-09-21 05:48:25
解答
-3≤log1/2(x)≤-1/2
1/2≤log2(x)≤3
f(x)=[log2(x/2)][log2(x/4)]
=[log2(x)-1][log2(x)-2]
=[log2(x)]^2-3log2(x)+2
=[log2(x)-3/2]^2-1/4
log2(x)=3/2时,有
f(x)min=-1/4
log2(x)=3时,有f(x)max=2
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