tan(π-α)*sin^2(α+π/2)*cos(2π-α)/cos^3(-α-π)*tan(2π-α) sin^2就是sin的_数学解答

tan(π-α)*sin^2(α+π/2)*cos(2π-α)/cos^3(-α-π)*tan(2π-α) sin^2就是sin的平方,下同

人气：410 ℃　时间：2020-04-10 23:13:17

解答

tan(π-α)=-tanα
sin(α+π/2)=-cosα
cos(2π-α)=cosα
cos(-α-π)=-cosα
tan(2π-α)=--tanα
代入=-1