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化简sin^2a+sin^2b+2sinasinbcos(a+b)
人气:179 ℃ 时间:2020-01-31 09:16:55
解答
sin^2a+sin^2b+2sinasinbcos(a+b)=sin^2a+sin^2b+2sinasinb(cosacosb-sinasinb)=(sin^2a-sin^2asin^2b)+(sin^2b-sin^2asin^2b)+2sinasinbcosacosb=sin^2acos^2b+sin^2bcos^2a+2sinasinbcosacosb=(sinacosb+sinbcos...
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