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求最大值和最小值 f(x) = cos x - sin x (-π ≤ x ≤ π)
人气:409 ℃ 时间:2020-05-19 00:36:49
解答
f(x) = cos x - sin x (-π ≤ x ≤ π)
=√2cos(x+π/4)
当cos(x+π/4)=1时即x=-π/4,f(x)max=√2
当cos(x+π/4)=-1时,即x=3π/4,f(x)min=-√2
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