∵x²-5x-2010=0∴[（x-2）²-（x-1）²+1]／（x-2）=[x²-4x+4-x²+2x-1+1]/(x-2)=(-2x+4)/(x-2)=-2(x-2)/(x-2)=-2………………………………………………………………∵a²-2a-4=0∴a&su...