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11+22+33+…+20020+20031除以7余数是______.
人气:201 ℃ 时间:2020-03-29 21:53:01
解答
11+22+33+…+20020+20031
=(11+20031)×[(20031-11)÷11+1]÷2,
=20042×[20020÷11+1]÷2,
=20042×[1820+1]÷2,
=20042×1821÷2,
=18248241.
18248241÷7=2606891…4.
故答案为:4.
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