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cota+(sina/(1+cosa))=1/sina 求证
人气:231 ℃ 时间:2020-02-05 06:35:04
解答
cota+sina/(1+cosa)
=cosa/sina+sina/(1+cosa)
=[cosa(1+cosa)+sin^2a]/sina(1+cosa)
=[cosa+cos^2a+sin^2a]/sina(1+cosa)
=(1+cosa)/sina(1+cosa)
=1/sina求证1/sin^2a+1/cos^2a=(1/sin^2a)(1/cos^2a)1/sin^2a+1/cos^2a=(cos^2a+sin^2a)/(sin^2a*cos^2a)=1/(sin^2acos^2a)=(1/sin^2a)*(1/cos^2a)(tana-sina)^2+(1-cosa)^2=((1/cosa)-1)^2(tana-sina)^2+(1-cosa)^2=(sina/cosa-sina)^2+(1-cosa)^2=sin^2a(1/cosa-1)^2+(1-cosa)^2=sin^2a(1-cosa)^2/cos^2a+(1-cosa)^2=(1-cosa)^2(sin^2a+cos^2a)/cos^2a=(1-cosa)^2/cos^2a=(1/cosa-1)^2cota^2a-cos^2a=cot^2acos^2a
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