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计算:(1-1/2²)(1-1/3²)......(1-1/2004²)(1-1/2005²)
人气:436 ℃ 时间:2020-04-04 21:54:50
解答
(1-1/2²)(1-1/3²)......(1-1/2004²)(1-1/2005²)=(1-1/2)(1+1/2)(1-1/3)(1+1/3).(1-1/2005)(1+1/2005)=1/2×3/2×2/3×4/3×...×2004/2005×2006/2005=1/2×2/3×3/4×...×2004/2005...
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