1)√3acosB+bsinA=√3c
√3sinA*cosB+sinB*sinA=√3sinC
sinA*cosB+√3/3sinAsinB=sinC=sinA*cosB+cosA*sinB
tanA=√3
A=60°
2)b=√3a,c=2,1/2absinC=√3
sinC=2/a²
cosC=(a²+b²-c²)/(2ab)=(2a²-2)/(√3a²)
sinC=√(1-cos²C)=√[(-a^4+8a²-4)/(3a^4)]
2/a²=√[(-a^4+8a²-4)/(3a^4)]
a^4-8a^2+16=0
a²=4
a=2