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计算;(1+x)(x的2次方+x分之x-1-x的3次方-x分之1-x)
人气:339 ℃ 时间:2020-04-30 00:12:37
解答
(1+x)[(x-1)/(x^2+x)-(1-x)/(x^3-x)]
=(1+x)[(x-1)/x(x+1)+(x-1)/x(x-1)(x+1)]
=(1+x)(x-1)/x(x+1)+(1+x)(x-1)/x(x-1)(x+1)
=(x-1)/x+1/x
=(x-1+1)/x
=x/x
=1
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