已知sinx=1/3,2π怎么算呀
人气:466 ℃ 时间:2020-05-13 07:19:51
解答
[sin(x/2)+cos(x/2)]²
=sin²(x/2)+2sin(x/2)cos(x/2)+cos²(x/2)
=1+sinx
=4/3
2ππ第三象限
所以
sin(x/2)<0,cos(x/2)<0
sin(x/2)+cos(x/2)<0
所以sin(x/2)+cos(x/2)=-2√3/3
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