y=cos[(1-x)π/2]=cos[π/2-πx/2]=sinπx/2于是最小正周期就是T=2π/w=2π/（π/2)=4还有根据定义f(x+4)=cos[(1-(x+4))π/2]=cos{(1-x)π/2-2π}=cos[(1-x)π/2]=f(x)即f(x+4)=f(x)于是最小正周期确定就是T=4...