函数y=cosπ/2x×cosπ/2(x-1)的最小正周期如果是：函数y=cosπ/2x×cos[(π/2)(x-1)]的最小正周期则有如下：y=cosπ/2x×cosπ/2(x-1)=cosπx/2*cos(πx/2-π/2)=cosπx/2*cos(π/2-πx/2)=cosπx/2*sinπx/2=(1/2)...