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老师,这个行列式用递推法怎么算啊?
0 1 0 0…0 0
1 0 1 0…0 0
0 1 0 1…0 0
……
0 0 0 0…1 0
n行n列
人气:124 ℃ 时间:2020-03-18 09:50:51
解答
按第1列展开Dn = (-1)^(2+1) * 1 * (-1)^(1+1) * 1 * Dn-2 = - Dn-2当 n=2k+1 (奇数) 时Dn = -Dn-2 = (-1)^2 Dn-4 = ... = (-1)^k D1 = 0当 n=2k (偶数) 时Dn = -Dn-2 = (-1)^2 Dn-4 = ... = (-1)^(k-1) D2 = (-1)^k...
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