∫(1→2)xf(x)dx=2,则∫(0→3)f(√(x+1)dx)=
人气：383 ℃ 时间：2020-05-13 21:04:02
解答
换元,令t=√(x+1),其中0则x=t^2-1
dx=2tdt
∫(0→3)f(√(x+1)dx)
=∫(1→2)f(t)*2tdt
=2∫(1→2)tf(t)dt
=2∫(1→2)xf(x)dx
=4
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