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设a=cos50°cos127°+cos40°cos37°,b=1-tan239°/1+tan239° c=√2/2√1-sin70°,则abc的大小关系是
人气:310 ℃ 时间:2020-10-01 11:29:32
解答
a=cos50°cos127°+cos40°cos37°
=cos50°cos127°+sin50°cos(127°-90°)
=cos50°cos127°+sin50°sin127°
=cos(50°-127°)
=cos(-77°)
=cos77°
cos90°
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