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已知tanx=2,则(2sin^2x-cos2x)/(cos^2x+1)
人气:116 ℃ 时间:2020-05-30 21:57:52
解答
原式=[2sin^2x-(cos^2x-sin^2x)]/(cos^2x+sin^2x+cos^2x)
=(3sin^2x-cos^2x)/(sin^2x+2cos^2x)
=(3tan^2x-1)/(tan^2x+2)
=(3*2^2-1)/(2^2+2)
=11/6
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