20082-20072+20062-20052+…+22-12=______.
人气:264 ℃ 时间:2019-11-16 16:30:52
解答
原式=(20082-20072)+(20062-20052)+…+(22-12),=(2008-2007)(2008+2007)+(2006-2005)(2006+2005)+…+(2-1)(2+1),=2008+2007+2006+2005+…+2+1,=(1+2008)×20082,=2017036.故答案为:2017036...
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