设x=2001
2001∧3＋2000×2000-2002×2001∧2÷2001∧3－2000×2002－2000×2001∧2
=x³+(x-1)(x-1)-(x+1)x²÷x³-(x-1)(x+1)-(x-1)x²
=x³+x²-2x+1-x³-x²÷x³-x²+1-x³+x²
=-2x+1
=-2×2001+1
=-4002+1
=-4001