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证明:tan^2a-sin^2a=tan^2*sin^2a
人气:162 ℃ 时间:2020-05-23 23:07:25
解答
tan^2a-sin^2a
=sin^2a/cos^2a-sin^2a
=(sin^2a-cos^2a*sin^2a)/cos^2a
=sin^2a(1-cos^2a)/cos^2a
=sin^2a*sin^2a/cos^2a
=tan^2*sin^2a
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