[(2-x)分之1+1]÷(x²-4)分之(x-3)×(x²+4x+4)分之x
={(x-2)分之[-1+(x-2)]}÷[(x+2)(x-2)]分之(x-3)×(x+2)²分之x
=(x-2)分之(x-3)×(x-3)分之[(x+2)(x-2)]×(x+2)²分之x
=(x+2)分之x
=(-1+2)分之(-1)
=-1
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