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数学
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求导 y=(3次根号下x)* (1-cosx)
人气:134 ℃ 时间:2019-09-27 20:09:07
解答
∵y=x^(1/3)*(1-cosx)
∴y'=(x^(1/3))'*(1-cosx)+x^(1/3)*(1-cosx)'
=(1-cosx)/(3x^(2/3))+x^(1/3)*sinx.
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