f(x)=2sin(-2x+pi/6)因为sin(-2x+pi/6)≤1所以f(x)≤2*1所以当sin(-2x+pi/6)=1时,f(x)的最大值为2由sin(-2x+pi/6)=1得：-2x+pi/6=pi/2+2k*pix=-1/6*pi-2k*pi k∈整数所以当x=-1/6*pi-2k*pi（k为整数）时,f(x)=2sin(-...