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初二下数学分式方程计算题
[ ( x-4 ) / ( x^2 - 1 ) ] ÷ [ ( x^2 - 3x - 4 ) / ( x^2 + 2x + 1 ) ] + (1 / x-1 )
其中 x = 2√2 + 1
人气:192 ℃ 时间:2020-05-09 09:16:28
解答
[ ( x-4 ) / ( x^2 - 1 ) ] ÷ [ ( x^2 - 3x - 4 ) / ( x^2 + 2x + 1 ) ] + (1 / x-1 )
=(x-4)/[(x+1)(x-1)×(x+1)²/[(x-4)(x+1)]+1/(x-1)
=1/(x-1)+1/(x-1)
=2/(x-1)
2/2√2
=√2/2
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