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已知tana=3,sin^2a+sinacosa+2cos^2a
人气:251 ℃ 时间:2020-05-18 05:14:31
解答
(sina)^2+sinacosa+2(cosa)^2
=1+ sinacosa+ (cosa)^2
= 1+ ( sina + cosa)/{ 1/cosa}
= 1+ ( tana + 1)/ {1/(cosa)^2}
= 1+ (3+1)/ (10) ( cosa = 1/√10)
= 7/5
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