你好!先化简 f(x)=2cosxsin(x+π/3)-√3*(sinx)^2+sinxcosx=2cosx[sinxcos(π/3)+cosxsin(π/3)]-√3*(sinx)^2+sinxcosx=sinxcosx+√3*(cosx)^2-√3*(sinx)^2+sinxcosx=2sinxcosx+√3*[(cosx)^2-(sinx)^2]=sin2x+√3*cos2x=2sin(2x+π/3)故,最小正周期为：2π/2=π