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已知函数f(x)=2cosxsin(x+60°)-根号3sin^2x+sinxcosx
求f(x)的最小正周期
人气:384 ℃ 时间:2019-09-27 05:47:46
解答
f(x)=2cosxsin(x+60°)-√3sin²x+sinxcosx
=2cosx(sinxcos60º+cosxsin60º)-√3sin²x+sinxcosx
=sinxcosx+√3cos²x-√3sin²x+sinxcosx
=2sinxcosx+√3(cos²x-sin²x)
=sin2x+√3cos2x
=2(1/2sin2x+√3/2cos2x)
=2sin(2x+π/3)
f(x)的最小正周期 T=2π/2=π
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