（一）ax²-x-2＞0.由题设可知,x≠0.故原不等式可化为a＞(x+2)/x².∴由题设应有(x+2)/x²＜1.===>x²-x-2＞0.===>(x+1)(x-2)＞0.===>x＜-1或x＞2.(二）由题设,原不等式可化为a＞(x+2)/x²=(2/x...