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设集合A={x丨x2+4x=0},B={x丨x2+2(m+1)x+m2-1=0}.若A∩B=B,求m的值?
人气:124 ℃ 时间:2020-06-20 07:42:35
解答
A={x丨x^2+4x=0}
={x| x=0 or -4 }
B={x丨x^2+2(m+1)x+m^2-1=0}
if A∩B=B
=> B is subset of A
when x=0
m^2-1 =0
m=1 or -1
when x= -4
16-8(m+1)+ m^2-1 =0
m^2-8m+7=0
m= 1 or 7
ie m =1 or -1 or 7我也是这样做的,可和答案不符啊,答案是m《1或m=1,是答案错了吗??
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