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计算①:2[a(b-3)-b(a-3)+3(a-b)] ②:2ab[3ab-4(0.5ab-1.5a²b)+2ab(2 -3a)
人气:196 ℃ 时间:2019-11-01 23:40:12
解答
1.2[a(b-3)-b(a-3)+3(a-b)] =2[ab-3a-ab+3b+3a-3b] =0
2.2ab[3ab-4(0.5ab-1.5a²b)+2ab(2 -3a)=2ab[3ab-2ab+6a²b+4ab-6a²b]=10a²b²步骤
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