(2x/x-3-x/x+3)×x^2-9/x,
={[2x(x+3)-x(x-3)]/(x+3)(x-3)}×[(x^2-9)/x]
=[2x^2+6x-x^2+3x)/(x^2-9)]×[(x^2-9)/x]
=(x^2+9x)/x
=x+9
=1+9
=10