> 数学 >
分解因式 ⑴2x^2-2x-1 ⑵2x^3-7x^2+2x+3
人气:481 ℃ 时间:2020-05-19 03:30:17
解答
⑴2x^2-2x-1
=2[x-(1-√3)/2][x-(1+√3)/2]
⑵2x^3-7x^2+2x+3
=2x³-2x²-5x²+5x-3x+3
=2x²(x-1)-5x(x-1)-3(x-1)
=(x-1)(2x²-5x-3)
=(x-1)(x-3)(2x+1)
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版