10(x+2)+x+138=[10x+(x+2)]^2
10x+20+x+138=(11x+2)^2
11x+2+156=(11x+2)^2
(11x+2)^2-(11x+2)-156=0
(11x+2-13)(11x+2-12)=0
(11x-11)(11x-10)=0
(x-1)(11x-10)=0
x=1或x=10/11