(10X + X + 2)^2 = 10X + 20 + X + 138
(11x+2)^2=11x+2+156
(11x+2)^2-(11x+2)-156=0
(11x+2-13)(11x+2+12)=0
(11x-11)(11x+14)=0
x=1或x=-14/11(11x+2-13)(11x+2+12)=0请问这步是怎么变来的。十字交叉分解怎么个十字相乘?(11x+2)^2-(11x+2)-156=0各项都没有系数,?(11x+2)^2-(11x+2)-156=0各项系数分别为:1,-1,-1561-13 ×1 12
