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若x/y=2/3,求3x方+5xy-2y方/x方-3xy-10y方的值
人气:402 ℃ 时间:2020-01-29 23:31:41
解答
x/y=2/3∴x=2/3y把 x=2/3y代入3x方+5xy-2y方/x方-3xy-10y方得原式=(4y²/3+10y²/3-2y²)/(4y²/9-2y²-10y²)=(8y²/3)/(-104y²/9)=-3/13
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