[5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(5xy^2)
=[5xy^2(x^2-3xy)+27x^6y^6]/(5xy^2)
=5xy^2(x^2-3xy)/(5xy^2)+27x^6y^6/(5xy^2)
=x^2-3xy+27x^5y^4/5和答案不一样哦！[5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(25x^2y^2)=[5xy^2(x^2-3xy)+27x^6y^6]/(25x^2y^2)=(5x^3y^2-15x^2y^3+27x^6y^6)/(25x^2y^2)=(5x-15y+27x^4y^4)/25=x/5-(3y)/5+(27x^4y^4)/25