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设cosθ+cos^2θ=1,则sin^2θ+sin^6θ+sin^8θ的值为
人气:316 ℃ 时间:2020-05-27 20:07:57
解答
cosθ+cos^2θ=1
cosθ=1-cos^2θ=sin^2θ
sin^2θ+sin^6θ+sin^8θ
=cosθ+cos^3θ+cos^4θ
=cosθ+cos^2θ(cosθ+cos^2θ)
=cosθ+cos^2θ*1
=cosθ+cos^2θ
=1
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