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已知X2-2x+y2+6y+10=0,求(x2-2xy)/(xy+y2)的值
人气:356 ℃ 时间:2020-01-29 20:27:24
解答
x²-2x+y²+6y+10=0,变换得(x-1)²+(y+3)²=0,∴x=1,y=-3

(x2-2xy)/(xy+y2)
=(1²-2*(-3))/(1*(-3)+(-3)²)
=7/6
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