> 数学 >
已知x2+y2-10x-6y+34=0,求(x-y/x+y)2÷x2-y2/xy×x2+2xy+y2/x2-xy 的值.
人气:452 ℃ 时间:2020-05-09 07:53:44
解答
你好

x²+y²-10x-6y+34=0
(x-5)²+(y-3)²=0
每项都大于等于0,只有等于0时上式才成立,所以
x=5
y=3
(x-y/x+y)²÷(x²-y²)/xy×(x²+2xy+y²)/(x²-xy)
=(x-y)²/(x+y)²×xy/[(x-y)(x+y)]×(x+y)²/x(x-y)
=y/(x+y)
=3/8

【数学辅导团】为您解答,不理解请追问,理解请及时选为满意回答!(*^__^*)谢谢!
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版