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x/(2-x)-(4-x²)/(x²+4x+4)
人气:225 ℃ 时间:2020-10-01 19:42:48
解答
原式= -x/(x-2)+(x+2)(x-2)/(x+2)²
= -x/(x-2)+(x-2)/(x+2)
=(-x²-2x+x²-4x+4)/(x+2)(x-2)
=(-6x+4)/(x²-4)我这样写可不可以=-x/(x-2)+(x+2)(x-2)/(x+2)²=- x/(x-2)+(x-2)/(x+2)= -(x²+2x-x²+4x-4)/(x+2)(x-2)= -(6x-4)/(x²-4)错==- [x/(x-2)-(x-2)/(x+2)]= -(x²+2x-x²+4x-4)/(x+2)(x-2)= -(6x-4)/(x²-4)我改过来了哦,对了请采纳吧
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