这样吧,我令方程右面为k,你自己想代入几都行(1+i)x-0.4iy=k (1)-0.4ix+(2+0.2i)y=0 (2)有(2)得：x=(2+0.2i)y/(0.4i),代入(1)得：(1.96+2.2i)y/(0.4i)=k,即：y=(0.4i)k/(1.96+2.2i)x=(2+0.2i)k/(1.96+2.2i)...