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若f(x)是偶函数,求f(1+更号2)-f(1减根号2 分之1)德值
人气:275 ℃ 时间:2019-08-31 19:08:04
解答
f(1+√2)-f(1/(1-√2))
=f(1/(√2-1))-f(1/(1-√2))(分子有理化)
=f(1/(√2-1))-f(-1/(√2-1))
=f(1/(√2-1))-f(1/(√2-1))(偶函数)
=0
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