3m/(x²+x-2)+(m+1)/(x+2)=2/(x-1)
两边都乘以(x+2)(x-1)得,3m+(m+1)(x-1)=2(x+2),∴(m+1-2)x=4-3m+m+1,∴x=(4m+1)/(m-1)
它是增根,那么它是-2或1
由(4m+1)/(m-1)=-2得,m=1/6；由(4m+1)/(m-1)=1得,m=-2/3
∴m=1/6或m=-2/3时,会产生增根.