> 数学 >
(cos20°-cos40°)/(sin20°-sin40°)=?
人气:248 ℃ 时间:2020-05-05 22:40:32
解答
(cos20°-cos40°)/(sin20°-sin40°)=[cos(30°-10°)-cos(30°+10°)]/[sin(30°-10°)-sin(30°+10°)] =[(cos30°cos10°+sin30°sin10°)-(cos30°cos10°-sin30°sin10°)]/[(sin30°cos10°-cos30°sin10°)-(sin30°cos10°-cos30°sin10°)]=(2sin30sin10°)/(-2cos30sin10°)=-tan30°=-√3/3
采纳哦
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版