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(m+n)^2-(2m-n)(2m+n)+(2m+n)^2因式分解
人气:466 ℃ 时间:2020-04-11 01:40:50
解答
(m+n)^2-(2m-n)(2m+n)+(2m+n)^2
=(m+n)^2-(2m+n)[(2m-n)-(2m+n)]
=(m+n)^2-(2m+n)(-2n)
=m^2+2mn+n^2+4mn+2n^2
=m^2+6mn+3n^2
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