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已知a为第二象限角,且sina=根号15/4,求sin(π-a)/((sin(a+π/2)+cosa+1)
人气:149 ℃ 时间:2019-08-20 18:48:29
解答
sina = √15 /4,cosa = - 1/4
sin(π-a) = sina = √15 /4,sin(a+π/2) = cosa = -1/4,
=> sin(π-a)/((sin(a+π/2)+cosa+1 ) = √15 /4 / ( -1/4 -1/4 + 1) = √15 / 2
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