方程 5/(x-2)+3/(2-x)=2 两边乘以x-2得5-3=2(x-2)∴x=1经检验：x=1是方程的解∴方程的解是x=1计算 (3x-2)/(x^2-x-2)+[1-1/(x+1)]/[1+1/(x-1)]=(3x-2)/[(x-2)(x+1)]+[x/(x+1)]/[x/(x-1)]=(3x-2(/[(x-2)(x+1)]+(x-1)...