试说明5的二次方×3的2n-1次方×2的n次方-3的n次方×6的n+2次方能被13整除
人气:437 ℃ 时间:2019-08-17 14:18:49
解答
5^2×3^(2n-1)×2^n-3^n×6^(n+2)=5^2×3^(2n-1)×2^n-3^n×3^(n+2)×2^(n+2)=5^2×3^(2n-1)×2^n-3^(2n+2)×2^(n+2)=3^(2n-1)×2^n×(25-3^3×2^2)=3^(2n-1)×2^n×(25-324)=-3^(2n-1)×2^n×299=-...
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