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已知函数f(x)满足x>=4,则f(x)=(1/2)^x,当x<4时,f(x)=f(x+1),则f(2+log2三对数)等于?
人气:316 ℃ 时间:2019-10-03 08:37:04
解答
2+log2(3)<4
而3+log2(3)>4
所以原式=f[2+log2(3)+1]
=f[3+log2(3)]
=1/2^[3+log2(3)]
=1/[2^3*2^log2(3)]
=1/(8*3)
=1/24
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